3.
Magnitude of magnetic field intensity at a point
around a current carrying conductor is B. If the
strength of current in the conductor becomes
double, then the magnitude of magnetic field
intensity at the point around the conductor is :
B
(1)
(2) B
12
B
(3)
(1) 2B
| 0 0 1 +
Answers
Answered by
0
Answer:
ans is B/4
Explanation:
(''_7_+$6_8&(_8&9&7$"gufjcyydp
Answered by
0
Corrected question: Magnitude of magnetic field intensity at a point around a current-carrying conductor is B. If the strength of the current in the conductor becomes double, then the magnitude of the magnetic field intensity at the point around the conductor is :
1) B (2) 12B (3) 3B (4) 2B
The magnetic field intensity will be twice, as compared to the initial field intensity when the current is doubled. So, the correct option will be 2B (option 4).
- The relation between the magnetic field in intensity placed at a distance 'd' from a current-carrying conductor is given by,
B = μI/2πd
⇒ B ∝ I
- So, we can see that the magnetic field intensity is directly proportional to the current passing through the current-carrying conductor.
- Through this we can easily conclude that if the current is increased by a factor of 2 the magnetic field intensity will also be increased by the same factor.
Therefore, the magnetic field intensity at that point will be 2B (option 4)
Similar questions