3 mem or 7 women can do a piece
of work in 32 days. how many
of days required by 7 men and 5 women to do twice the piece of work ?
Answers
Answered by
1
Step-by-step explanation:
Let work done by 1 man in 1 day =m
work done by 1 woman in 1 day =w
Work done by 3 men in 1 day =1/32
3m=1/32
m=1/96
Work done by 7 men in 1 day =1/32
7w=132
w=1/224
Work done by 7 men and 5 women in 1 day =7m+5w
=7/96+5/224
=49+15/672
=64/672
=2/21
Therefore, 7 men and 5 women can do the same work in 2/21 days
To do work twice as large, time required
=21/2×2
=21 days
HOPE IT HELPS YOU !!
bd4968058:
this sum is for compitative exam. so i required quick steps
Answered by
0
Answer:
NO MEN REQUIRED .............
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