3 men, 2women and 2 children are to be seated in a 8 seated car. Car has 2 seats in front row
including a driver seat and 3 seats each in second and third row. Assuming 2 of the men and 1
women can drive the car. Then the probability that no children sits in the front row, when the car is
driven is:
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Step-by-step explanation:
The probability that no children sits in front row is 0 by 8
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probability
Step-by-step explanation:
As 2 men and 1 women can drive the car so driver can be selected in 3 ways . also if no child sits in the front row so the adjacent seat to driver can be filled in 4 ways . now the back 6 seats can be taken by rest persons in 5.4.3.2.1 ways. so the favourable cases are 3.4.5.4.3.2.1. also the total number of ways are 8c7 multiplied by 7! so required probability is their ratio
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