3 Men, A, B, and C complete a work in such a way that A works for all the day. B works for 1st and 2nd day and C works for 3rd, 4th and 5th day. If B+C can do as much work in 2 days as A alone does in 3 days. In how many days A, B and C alone do the work If B+C can complete the whole work without the help of A in 6 days ?<br />
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Answer:
A can complete the work in 9 days
B can complete the work in 18 days
C can complete the work in 9 days
Step-by-step explanation:
B and C can do as much work in 2 days as A does in 3 days (Given)
∵ B and C finish a work in 6 days (Note: 2 multiplied by 3 = 6)
∴ A alone can finish the work in 9 days ( 3 multiplied by 3)
Let work done by B in one day is and work done by C in one day is
Work done by A in one day =
According to the question
Again, since B and C can complete the work in 6 days
Multiplying eq (ii) by 2 and subtracting it from eq (i),
Putting the value of y in eq (ii)
Thuss, in 1 day B completes work
Therefore, B can complete the work in 18 days
Similarly, C can complete the work in 9 days (∵ in 1 day C does work)
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