3 men and 4 boys can complete a certain amount of work in 28 days, where as 4 men and 6 boys can complete the same work in 20 days. find the number of boys only to complete the same work
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10 boys can complete the work in 28 days and 14 boys can complete the work in 20 days.
Let one day work of men be m and one day work of boys be b.
Three men and four boys take 28 days to complete the work.
4 men and 6 boys can complete the same work in 20 days.
=> (3m + 4b)28 = (4m + 6b)20
=> 21m + 28b = 20m + 30b
=> m = 2b
One days work of men = 2 days work of boy.
3 men and 4 boys take 28 days
=> 6 boys and 4 boys take 28 days (1 man = 2boy)
=> 10 boys are needed to complete the work in 28 days .
Similarly 14 boys are needed to complete the work in 20 days.
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