Question

3 men and 4 boys can complete a piece of work in 6 days whereas the same
work can be done by 5 men and 2 boys in 5 days. Find how many days will
be required for one man to complete that work?

Answer 1

Answer:

in one day

Step-by-step explanation:

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Answer 2

Answer:

$hi$

Step-by-step explanation:

Number of day taken by 1 men = x days

And of boy = y days

Work done by 1 men in 1 day = 1x1x

Work done 1 boy in 1 day = 1y

1y

According to the first condition

According to the second condition

3x+4y

Let 1x=v and 1y=u1x=v and 1y=u

On multiplying equation (1) by 3 and equation (2) by 4, we get

12v+18u=35..(3)12v+16u=47(4)12v+18u=35(3)12v+16u=47

Subtracting equation (3) from (4)

⇒12v−12v+18u−16u=35−47⇒2u=135⇒u=170∴y=70⇒12v−12v+18u−16u=35−47⇒2u=135⇒u=170∴y=70

Putting value of y in equation (1)

⇒4x+670=15⇒1x=14×(15−670)⇒x=35⇒4x+670=15⇒1x=14×(15−670)⇒x=35

Hence, one man alone can finish work in 35 days and one boy in 70 days.