Question

3 men and 4 boys can do a piece of work in 14 days. Frame the equation considering one man finishes the work in x days and one boy finishes the work in y days 
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Answer 1

Answer:Let one man's one day's work be x

Let one boy's one day's work be y

According to first condition,

3x+4y=  

14

1

​  

     .......Equation 1

According to second condition,

4x+6Y=  

10

1

​  

     .......Equation 2

Multiplying Equation 1 by 4 and Equation 2 by 3,

12x+16y=  

14

4

​  

     .....Equation 3

12x+18y=  

10

3

​  

     .....Equation 4

Now solving Equation 3 and 4 simultaneously by substracting Equation 3 by Equation 4,

we get,

∴−2y=  

14

4

​  

−  

10

3

​  

 

∴−2y=  

140

40−42

​  

 

∴y=  

140

1

​  

 

Putting the value of y in equation 1, we get,

3x+  

140

4

​  

=  

14

1

​  

 

∴x=  

70

1

​  

 

Hence one man's one day  work is  

70

1

​  

 

∴ one man completes the whole work in 70 days.

Step-by-step explanation: