Math, asked by lucendra, 6 months ago

3 men can compete a piece of work in 6 days. Two days after they started the work, 3 more men joined them . How many days will they take to complete the remaining work?​

Answers

Answered by pointgame122
1

Answer:

2 days

Step-by-step explanation:

3 men×6 days=(3 men×2 days)+[(3+3)men× D days]  

18−6=6×D

12/6=D                                                                                                  (D is days)

Answered by Dhruva26
1

This is the case of inverse proportion.

3 men in the beginning,

6 men afterwards.

So the equation will be

3:6 :: X:4

6X=12

X=2

The remaining work will be completed in 2 days.

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