3 men can compete a piece of work in 6 days. Two days after they started the work, 3 more men joined them . How many days will they take to complete the remaining work?
Answers
Answered by
1
Answer:
2 days
Step-by-step explanation:
3 men×6 days=(3 men×2 days)+[(3+3)men× D days]
18−6=6×D
12/6=D (D is days)
Answered by
1
This is the case of inverse proportion.
3 men in the beginning,
6 men afterwards.
So the equation will be
3:6 :: X:4
6X=12
X=2
The remaining work will be completed in 2 days.
Similar questions