Question

3 men or 6 womencan do a piece of work in 20 days. in how many days will12 men and 8 wonendo the same work

Answer 1

Work done by 3 men in 1 day = [tex] \frac{1}{20} [/tex]
Work done by 1 man in 1 day = [tex] \frac{1}{60} [/tex]

Work done by 6 women in 1 day=[tex] \frac{1}{20} [/tex]
Work done by 1 woman in 1 day = [tex] \frac{1}{120} [/tex]

12 men & 8 women in 1 day = 12× [tex] \frac{1}{60} [/tex] +  8×  [/tex]\frac{1}{120} [/tex]
                                            =$\frac{1}{5} + \frac{1}{15}$
                                             = [tex] \frac{3+1}{15} [/tex]
                                              =[tex] \frac{4}{15} [/tex]

12 men & 8 women will require =$\frac{15}{4}$ days OR 3.75 days