Question

3 minus root 2 is an irrational number prove that ​

Answer 1

hope it helps u..........

Answer 2

Step-by-step explanation:

Let

$3 - \sqrt{2}$

be an rational number

Then,

it must be in the form of p/q where q not equal to 0

so,

$3 - \sqrt{2}$

= p/q

=p-3/q= -root2

here,

p-3/q is rational number

but,

-root2 is irrational

Therefore,

$3 - \sqrt{2}$

is irrational number