Question

3 minus root 5 upon 3 plus 2 root 5 = a root 5 minus 19/11 b

Answer 1

Solution:

LHS = (3-√5)/(3+2√5)

/* Rationalising the denominator */

=[(3-√5)(3-2√5)]/[(3+2√5)(3-2√5)]

=[9-6√5-3√5+10]/[(3²-(2√5)²]

/* (a+b)(a-b) = a²-b² */

= [19-9√5]/(9-20)

= [19-9√5]/(-11)

=(-19/11)-(9/-11)√5

=(-19/11)+(9/11)√5 ---(1)

Now,

LHS = RHS

(9/11)√5-(19/11)1

=a√5-(19/11)b

Compare both sides, we get

a = 9/11 ,

b = 1

••••

Answer 2

Answer:

Step-by-step explanation: