Question

3 ML of solution sodium sulphate are mixed with 3ML of barium chloride solution in a test tube. (a)Write the chemical name of the product formed. (b)Identify the chemical reaction and define it. (c) Write the chemical equation for the reaction. No spam please. I mark branliest who give correct and report who spam.

Answer 1

Answer:

a sodium chloride

b it is double displacement reaction it is a reaction in which the higher reactive metal displace lower reactive metal

c NaSo4+Bacl2= NaCl+ Ba So4

Explanation:

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Answer 2

Answers with respect to reaction of barium chloride and sodium sulphate are as follows

(a) The chemical reaction yields the products barium sulphate and sodium chloride.

(b) The chemical reaction involved here is double displacement reaction. Double displacement reaction is defined as the reaction where two reactants dissociate into ions, which are exchanged in the solution to form new products.

(c) The chemical equation for the reaction is as follows -

BaCl2 + Na2SO4 --> BaSo4 + 2NaCl

Barium sulphate is seen as the precipitate and sodium chloride remains dissolved.