Question

3. Mohan walks 17 m North-East and 8 m South. How far is he from his initial
position?
मोहन 17 मीटर उत्तर-पूर्व और 8 मीटर दक्षिण में चलता है, वह अपने प्रारंभिक स्थान से कितनी दूरी
पर है।​

Answer 1

Answer: 15m

Explanation : By pythagoras theorem

AC^2=AB^2+CB^2

CB^2= AB^2-AC^2

289-64=225

=15 ANS

Answer 2

Answer:

15 m

Step-by-step explanation:

By Pythagoras property, you should solve thia