Question

3 moles of ideal gas r expanded isothermally from volume of 300 cmcube to 2.5 litre at 300 k against pressure of 1.9 atm. calculate work done in L atm and joules​

Answer 1

Answer:

As the gas is expanded against constant pressure so,

Work done, W=−PΔV

V

2

= final volume =2.5 L

V

1

= initial volume =300 cm

3

=0.3 L

P is constant external pressure =1.9 atm

W=−P(V

2

−V

1

)

=−1.9×(2.5−0.3)

=−4.18 L.atm

In joules we know,

1 atm.L=101.325 J

Hence, −4.18 L.atm=−4.18×101.3=−423.5 J

Answer 2

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