Chemistry, asked by anjali626133, 10 months ago

3 moles of N2 react with 2 moles of O2 in a 2 litre container to form one more of an what will be the number of moles of O2 per litre at equilibrium​


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Answers

Answered by ravi9848267328
8

Answer:

So 0.5 mole N2 reacts with 0.5 mole O2 to form 1.0 mole of Nitric Oxide.

Initially there was 2 moles of O2.

0.5 mole of O2 was uesd in the reaction. After the reaction is over, at equilibrium the number of moles of O2 remaining is

Explanation:

N2 + O2 > 2NO

3 moles + 2 moles > 0 moles (at start)

(3-0.5 ) ( 2– 0.5 ) (1 mole)

So 1.5 moles of oxygen will be at equilibrium.

concentration of O2 at equilibrium = 1.5 mole/ 2 litre = 0.75 moles/litre


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