3 moles of N2 react with 2 moles of O2 in a 2 litre container to form one more of an what will be the number of moles of O2 per litre at equilibrium
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So 0.5 mole N2 reacts with 0.5 mole O2 to form 1.0 mole of Nitric Oxide.
Initially there was 2 moles of O2.
0.5 mole of O2 was uesd in the reaction. After the reaction is over, at equilibrium the number of moles of O2 remaining is
Explanation:
N2 + O2 > 2NO
3 moles + 2 moles > 0 moles (at start)
(3-0.5 ) ( 2– 0.5 ) (1 mole)
So 1.5 moles of oxygen will be at equilibrium.
concentration of O2 at equilibrium = 1.5 mole/ 2 litre = 0.75 moles/litre
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