3^n+1+3^n/ 3^n-3^n-1
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2
Answer:
3
Explanation:
It can be written as, [(3^n+(3^n*3^1)] / {3^n+(3^n*3^-1)}
by taking 3^n common,
3^n(1+3^1)/3^n(1+3^-1)
cancelled 3^n,
=> (1+3)/(1+1/3)
=> 4/(4/3)
=> (4*3)/4 = 3
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