Question

3^n÷(-3^n) please solve​

Answer 1

Answer will be -1
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Answer 2

$\frac{3^n}{(-3)^n}=-1,\ if \ n\ is odd . \\ \\ \\ \frac{3^n}{(-3)^n}=1,\ if \ n\ is even.$

$E.g.: Let \ n=1. \\ \\ \frac{3^n}{(-3)^n}=\frac{3^1}{(-3)^1}=\frac{3}{(-3)}=-1 \\ \\ \\ Let \ n=2. \\ \\ \frac{3^n}{(-3)^n}=\frac{3^2}{(-3)^2}=\frac{9}{9}=1$

$\bold{Reason:} \\ \\ \\ Let \ n=2k-1,\ \ such that \ n\ is odd. \\ \\ \frac{3^n}{(-3)^n}=\frac{3^{2k-1}}{(-3)^{2k-1}}=\frac{3^{2k} \div 3}{(-3)^{2k} \div (-3)}=\frac{9^k \times \frac{1}{3}}{9^k \times \frac{1}{-3}}=\frac{\frac{1}{3}}{\frac{1}{-3}} \\ \\ = \frac{1}{3} \div \frac{1}{-3}=\frac{1}{3}\times-3=\frac{-3}{3}=-1$

$Let \ n=2k,\ \ such that \ n\ is even. \\ \\ \frac{3^n}{(-3)^n}=\frac{3^{2k}}{(-3)^{2k}}=\frac{9^k}{9^k}=1$

$That's all! \\ \\ Hope this helps. \\ \\ Please ask me if any doubts. \\ \\ Also please mark it as the brainliest. \\ \\ \\ Thank you. :-)$