Question

3(n-4)+2(4n-5)=5(n+2)+16​

Answer 1

Step-by-step explanation:

3(n-4)+2(4n-5)=5(n+2)+16

3n-12+8n-10=5n+10+16

11n-22=5n+26

11n-5n=26+22

6n=48

n=48/6

n=8

Answer 2

Solution-

3(n-4)+2(4n-5) = 5(n+2)+16

or, 3n-12+8n-10 = 5n+10+16

or, (3n+8n)+(-12-10) = 5n+(10+16)

or, 11n-22 = 5n+26

or, 11n-5n = 26+22

or, 6n = 48

or, n = 48/6

or, n = 8

Hence, n = 8.

Verify-

3(n-4)+2(4n-5) = 5(n+2)+16

or, 3(8-4)+2(4×8-5)=5(8+2)+16

or, 3×4+2(32-5) = 5×10+16

or, 3×4+2×27 = 50+16

or, 12+54 = 66

or, 66 = 66

Hence, L.H.S =R.H.S.