3 no.s are in the ratio 1:2:3 the sum of their cubes are 7776 find the numbers
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The numbers are 1x, 2x,3x
Sum of their cubes=7776
therefore,(1x)^3+(2x)^3+(3x)^3=7776
1x^3+8x^3+27x^3=7776
36x^3=7776
x^3=7776/36
x^3=216
x=(cuberoot)216
x=6(ams)
#hopeit helps #markbrainliest
@hermoinegranger 7
Sum of their cubes=7776
therefore,(1x)^3+(2x)^3+(3x)^3=7776
1x^3+8x^3+27x^3=7776
36x^3=7776
x^3=7776/36
x^3=216
x=(cuberoot)216
x=6(ams)
#hopeit helps #markbrainliest
@hermoinegranger 7
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