3 number. are AP Is 27 and product648 find the numbers
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Given: Sum of first three terms is 27 Let us assume the first three terms as a – d, a, a + d [where a is the first term and d is the common difference] So, sum of first three terms is a – d + a + a + d = 27 3a = 27 a = 9 It is given that the product of three terms is 648 So, a3 – ad2 = 648 Substituting the value of a = 9, we get 93 – 9d2 = 648 729 – 9d2 = 648 81 = 9d2 d = 3 or d = – 3 Hence, the given terms are a – d, a, a + d which is 6, 9, 12.Read more on Sarthaks.com - https://www.sarthaks.com/802598/three-numbers-are-in-a-p-if-the-sum-of-these-numbers-be-27-and-the-product-648-find-the-numbers
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