Question

3. Number of integral value of x satisfying x^2 - 2x–4<0​

Answer 1

Answer:

3

Step-by-step explanation:

x²-2x-4 < 0

x = 2 ± √(4+4) /2

x = 2±2√2 /2

x = 1±√2

∴ x ∈ (1-√2,1+√2)

Since √2 = 1.41

1-√2 = 1-1.41 = -0.41

1+√2 = 1+1.41 = 2.41

∴Integral solutions = 0,1,2