Math, asked by vaishnavi11129, 2 months ago

3 numbers are in ratio 1:2:3.the sum of their cubes is 0.002304 .find the number​

Answers

Answered by bothraparshv36
0

Answer:

hh

Step-by-step explanation:

1x 2x 3x = 0.002304. now you can do

Answered by aarushisharma19805
1

Answer:

let first ratio = 1x

let second ratio = 2x

let third ratio = 3x

According to the question

(1x {)}^{3}  + (2x {)}^{3}  + (3x {)}^{3}  = 0.002304 \\ x {}^{3}  + 8x {}^{3}  + 27x {}^{3 }  = 0.002304 \\ 36x {}^{3}  = 0.002304 \\ x {}^{3}  = \frac{2304}{1000000 \times 36}   \\ x {}^{3 }  =  \frac{64}{1000000}  \\ x =  \sqrt[3]{ \frac{64}{1000000} }  \\ x =  \frac{4}{100}  \\ x = 0.04

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