Math, asked by himanshumor, 1 year ago

3 numbers are in the ratio 3:4:5. if the sum of the largest and the smallest number exceeds the 3rd number by 64 find the number

Answers

Answered by Jeet1508
3
HERE IS THE ANSWER FRIEND ....
LET,
3NOS.IS 3X,4X,5X RESPECTIVELY.
A2Q
(5X+3X)-4X=64
OR,4X=64
OR,X=16
THEN,3NOS. ARE 48,64,80.
HOPE IT WILL HELP YOU.

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Answered by preeneer
0
sum of L and S=3x+5x=5x+64. 8x-5x=64,3x=64,x=21.3
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