3 numbers are in the ratio 4:5:3, the sum of whose squares is 1250.Find the numbers.
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lets take three numbers in ratio 4:5:3be 4k,5k,3k. Sum of squares of these numbers=
![16 {k}^{2} + 25 {k}^{2} + 9 {k}^{2} = 50 {k}^{2} 16 {k}^{2} + 25 {k}^{2} + 9 {k}^{2} = 50 {k}^{2}](https://tex.z-dn.net/?f=16+%7Bk%7D%5E%7B2%7D+%2B+25+%7Bk%7D%5E%7B2%7D+++%2B+9+%7Bk%7D%5E%7B2%7D+%3D+50+%7Bk%7D%5E%7B2%7D)
=> 1250=
![50 {k}^{2} 50 {k}^{2}](https://tex.z-dn.net/?f=50+%7Bk%7D%5E%7B2%7D+)
=>25=
![{k}^{2} {k}^{2}](https://tex.z-dn.net/?f=+%7Bk%7D%5E%7B2%7D)
=>k=5 or-5(Not possible)
=>numbers are 20,25 and 15 respectively.
=> 1250=
=>25=
=>k=5 or-5(Not possible)
=>numbers are 20,25 and 15 respectively.
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