3 numbers in ap whose sum is 27 and sum of squares is 241
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Hello.
Let's begin solving.
Let the three numbers be a - d, a, a+d.
a-d + a + a + d = 27
3a = 27
a = 9
(a-d)(a)(a+d) = 648
a(a2 - d2) = 648
9(92 - d2) = 648
92 - d2 = 72
d2 = 81 - 72
d2 = 9
d = 3
The numbers are 6,9,12
Hope it helps.
Let's begin solving.
Let the three numbers be a - d, a, a+d.
a-d + a + a + d = 27
3a = 27
a = 9
(a-d)(a)(a+d) = 648
a(a2 - d2) = 648
9(92 - d2) = 648
92 - d2 = 72
d2 = 81 - 72
d2 = 9
d = 3
The numbers are 6,9,12
Hope it helps.
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