Math, asked by mushkan4564, 1 year ago

3 numbers which are co prime to each other are such that the product of the first two is 119 and that of the last two is e391.what is the sum of the three numbers

Answers

Answered by CoruscatingGarçon
4

Since the numbers are co-prime, their HCF = 1 Product of first two numbers = 119 Product of last two numbers = 391 The middle number is common in both of these products. Hence if we take HCF of 119 and 391, we get the common middle number. HCF of 119 and 391 = 17 So, Middle Number = 17 First Number = 119/17 = 7 Last Number = 391/17 = 23 Sum of the three numbers = 7 + 17 + 23 = 47

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