Question

3. One container contains a mixture of spirit and water in the ratio 2: 3 and
another contains the mixture of spirit and water in the ratio 3: 2. How much
quantity from the second should be mixed with 10 litres of the first so that the
resultant mixture has ratio of 4: 5? (IBPS PRE 2018)​

Answer 1

Answer:

2 6/7 litres or 2.86 litres

Step-by-step explanation:

Fisrt Container = 2:3

10 litre = 4 litre spirit + 6 litre water

Second container= 3:2

new mixture = 4:5

$\frac{4 + 3x}{6 + 2x} = \frac{4}{5}$

$x = \frac{4}{7}$

second container spirit and water ratio = 3x:2x

Quantity of second liquid added = 5x = 20/7 litres = 2 6/7 litres = 2.86 ltres

Answer 2

Answer:

can you solve this question by the butterfly method?