Question

3. One mole of a gas occupying 5 Litres is expanded against a constant external pressure of 1 atm
to a volume of 20 Litres. Calculate work done in Joules.​

Answer 1

Explanation:

olution:- (A) −1.215×10

3

J

As we know that, work done by a system against an external pressure is given as :

W=−P

ext.

ΔV

Given:-

P

ext.

=1atm

V

f

=15L

V

i

=3L

∴W=−1(15−3)

⇒W=−12L−atm=−1215.96J=1.215×10

3

J

[1 L atm = 101.325 J]

Hence, the work done by the system is −1.215×10

3

J.