Question

3. One vessel contains mixture of milk and water in the ratio Of 8:5 another vessel Contains mixture of milk and water in the ratio of 6:7. In what ratio should the mixture of these two variables of milk be mixed to prepare a mixture of milk and water in the ratio 7:5 ​

Answer 1

Answer:

19:5

For This Question

Answer 2

Given :

• One vessel contains mixture of milk and water in the ratio of 8:5
• Another vessel contains mixture of milk and water in the ratio of 6:7

To find : The ratio in which the mixture of these two variables of milk be mixed to prepare a mixture of milk and water in the ratio 7:5

Solution :

The mixtures should be mixed in the ratio of 19:5

Let, the amount of two mixtures = x and y ,respectively.

So, in x amount of first mixture :

• Amount of milk = 8x
• Amount of water = 5x

And, in y amount of second mixture :

• Amount of milk = 6y
• Amount of water = 7y

Total amount of milk in final mixture = (8x+6y)

Total amount of water in final mixture = (5x+7y)

Ratio of milk and water in final mixture = (8x+6y) : (5x+7y)

According to the data mentioned in the question,

(8x+6y) : (5x+7y) = 7:5

(8x+6y) / (5x+7y) = 7/5

40x+30y = 35x+49y

40x-35x = 49y-30y

5x = 19y

5x/19y = 1

x/y = 19/5

x:y = 19:5

(This will be considered as the final result.)

Hence, the two mixtures should be mixed in the ratio of 19:5