Question

3.
or
1
273
Pressure-Temperature
Relationship
Gay-Lussac's Law. It states that: At constant volume, the
pressure of a given mass of a gas increases by
of its
original pressure at 0°C for every 1°C rise in temperature.
Mathematically, this relationship can be expressed as :
Po
P = Po + x t°C
273
the pressure, at​

Answer 1

Answer:

3

Explanation:

the anwser is 3 bro u see in it ur book

Answer 2

Answer:

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