Question

3
os. A constant forece of friction
of 500N is acting on a body of
mass 200 kg moving initially
with a speed of 15 m/s How
Long does the body take to stop
what distance
Bill it cover
before coming
To rest ? ?​

Answer 1

Explanation:

Retarding force,

F = –500 N

Mass of the body, m = 200 kg

Initial velocity of the body, u = 15 m/s

Final velocity of the body, v = 0

Using Newton’s second law of motion, the acceleration (a) produced in the body can be calculated as:

F = ma

=> –500 = 200 × a

=> a= -500/200 = -2.5 m/s^2

Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as:

v = u + at

=> t= -u/a = -15/-2.5= 6 sec

hope this helps u