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Out of 100 persons in a group, 72 persons speak English and 43 perseus speak French.
Each one out of 100 persons speak at least one language. Then how many speak only
English ? How many speak only French ? How many of them speak English and French
both?
Answers
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let A→ Set of people who speak English.
B→ Set of people who speak French.
A−B→ Set of people who speak English and not French.
B−A→ Set of people who speak French and not English.
A∩B→ Set of people who speak both English and French.
Given
n(A)=72n(B)=43n(A∪B)=100
Now,
n(A∪B)=n(A)+n(B)−n(A∪B)
=72+43−100
=15
∴ Number of persons who speak both English and French are 15
n(A)=n(A−B)+n(A∩B)
⇒n(A−B)=n(A)−n(A∩B)
=72−15
=57
And
⇒n(B−A)=n(B)−n(A∩B)
=43−15
=28
∴ Number of people speaking English only are 57.
and Number of people speaking French only are 28.
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Let U be the set of all the persons, E be the set of persons who speak English, F be the set of persons who speak French and x people speak both the languages.
Since, each one out of 100 persons speak at least one language.
∴ n(U) = n(E ∪ F) = 100
∴ 72 – x + x + 43 – x = 100 ∴ 115 – x = 100
∴ x = 115 – 100 = 15.
Number of people who speak English and French = 15
Number of people who speak only English = 72 – x = 72 – 15 = 57
Number of people who speak only French = 43 – x = 43 – 15 = 28