Question

3. Pand Q are any two points lying on the sides DC and AD respectively of a parallelogi
ABCD. Show that ar (APB) = ar (BQC).
​

Answer 1

Step-by-step explanation:

It can be observed that ΔBQC and parallelogram ABCD lie on the same base BC and these are between the same parallel lines AD and BC.

∴ Area (ΔBQC) = 1/2 Area (ABCD)  ----- (1)

Similarly,

It can be observed ΔAPB and parallelogram ABCD lie on the same base AB and between the same parallel lines AB and DC.

∴ Area (ΔAPB) = 1/2 Area (ABCD)  ------ (2)

On solving (1) and (2), we get

Area (ΔBQC) = Area (ΔAPB)

Hope it helps!