3 particles are performing SHM such that the amplitude of the individual particles is given as 2 units and 3 units and 4 units.
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Answer:
x
1
=Asinwt
x
2
=Asin(wt+ϕ) distance between them is
(x
2
−x
1
)=Asin(wt+ϕ)−Asin(wt)
=A[2cos(wt+ϕ)−Asin(wt)]
=A[2cos(wt
2
ϕ
)sin(
2
ϕ
)]
(x
2
−x
1
) will be max if cos(wt+
2
π
)=1
∴(x
2
−x
1
)
max
=2Asin(
2
ϕ
)
A=2Asin(
2
ϕ
)
⟹
2
ϕ
=30
o
=
6
π
∴ϕ=60
o
or
3
π
radian
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