3 people A,B,C weigh themselves in particular order first A,B,C weigh themselves individually and then ab BC CA and abc together respectively the recorded wait for the last measures is 180 kg the average of seven measures is
Answers
Answered by
3
Answer:
720/7 kgs / 102.82 kgs .
Step-by-step explanation:
they are told that , (A+B+C)'s recorded weigh is 180 .
then ,
= a+b+c+ab+bc+ca+(a+b+c)/7
= 4/7*(A+B+C) . ( 4 because everyone has to weigh themselves 4 times in total )
= 4/7*180 = 720/7 kgs .
Similar questions