Question

3. Perimeters of two similar triangles are 50 cm and 40cm. If one side of 1st
triangle is 10 cm,then corresponding side of 2nd triangle =
A) 6 cm

B) 12.5 cm

C) 10 cm

D) 8 cm​

Answer 1

Answer:

8cm (option D is the right answer)

Step-by-step explanation:

Perimeters of two similar triangles are 50 cm (let p1) and 40cm (let p2).

one side of 1st triangle is 10 cm (let a1)

if one of their corresponding sides are a1 and a2 respectively, then,

p1/p2 = a1/a2

=> 50/40 = 10/a2

=> 5/4 = 10/a2

=> a2 = 10×4/5 = 8