Math, asked by tanmoyghosh1919, 11 months ago

3 persons went to a restaurant they recieved a bill of 30 rupee they paid the 30 rupee to the waiter . When the waiter give to his manager the manager said that there is a discount of 5 rupee when the waiter was taking the money back to the 3 men the waiter become greedy he took 2 rupee from the 5 rupee and he paid the 3 rupee to each men.So the three men paid 9 rupee so 3*9=27and the waiter took 2 rupee so 27+2=29 so where is the 1 rupee​

Answers

Answered by Anonymous
150

\huge\underline\mathfrak\pink{Explanation}

Bill received by the three persons = ₹ 30 ( Given )

Discount on the food = ₹ 5 ( Given )

Therefore, total cost of food = ₹( Bill - Discount )

= ₹ ( 30 - 5 )

= ₹ 25

It is given that the waiter took 2 rupees from the 5 rupees because of his greediness.

So, he return 1 - 1 rupee to 3 persons.

Hence, The total bill given by three persons = 9 × 3 => ₹ 27

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Also, we know that the waiter took 2 rupees which was already counted in that bill, so, it'll be 27 and the waiter return 3 rupee to the persons,

Add money in both cases that is equal to 27 + 3 = 30

____________________

Answered by Anonymous
52

Solution :-

Bill received by the 3 persons = Rs 30

Discount given by manager = Rs 5

So, Cost for food = Rs (30 - 5) = Rs 5

But, the waiter become greedy So, he took 2 rupees from the 5 rupees.

Waiter return one - one rupee to the three persons. So, Three persons total bills = 9 × 3 = Rs 27

As we know that, the waiter took Rs 2 and also that it was already counted in the bill so that it becomes Rs 27.

And the money given to three persons is Rs 3 when we add this money to the bill it will become Rs 30.

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