Question

3 pieces of timber 42 metre 49 metre 63 metre long have to divided into planks of the same lengths what is the greatest possible length of each plan ?​

Answer 1

Answer:

the greatest possible length of each plank is 7m

Step-by-step explanation:

the length of three pieces of timber are 42m, 49m and 63m respectively.

we have to divide the timber into equal length of planks

So, greatest possible of each plank = HCF (42,49,63)

prime factorization :-

42 = 2×3×7

49 = 7×7

63 = 3×3×7

therefore, HCF = product of smallest power of each comman prime factor involved in numbers = 7

Hence, the greatest possible length of each plank is 7m.

Answer 2

Answer:

i am not these answer

Step-by-step explanation:

i am not these answer