Question

3 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take if only 2 pipes of the same type are used?​

Answer 1

Answer:

Let the desired time to fill the tank be x minutes.

In 80 mins a tank is filled by 6 pipes

Lesser the number of pipes more will be the time required by it to fill the tank.

So, this is a case of inverse proportion.

Hence, 80×6=x×5

⇒

5

80×6

=x

⇒x=96

Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.

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