3 pipes can fill a tank in 10,15 and 20 hrs respectively. Of the three taps are opened one after another in the given order with a certain time gap between them the tank fill in 20 hrs. Find the time gap?
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Time taken by the three taps together to fill the tank = (1/10 + 1/15 + 1/20)^-1
=60/13hrs
Total time taken including the 2 gaps (one between 1st and 2nd tap and the other between 2nd and 3rd tap)
= 20 hrs
Time taken by the taps to fill the tank without any time gap = 3*60/13
=180/13 (as the taps were open in succession not together)
Time of the 2 gaps = 20 - 180/13
=80/13
Time of each gap = 80/13÷2
=40/13 hrs.
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