3 points ii. What is the minimum mass of Al(OH)3 that can be obtained by reaction of 13.4 gm of AlCl3 with 10 gm NaOH acc to following equation (at. mass of Al=27) AICI3 + 3 NaOH -----> Al(OH)3 + 3NaCl 3
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8na 9 cl10 9 answer
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