Question

3 points
Q11. In the fig line mll linen
and line lis a transversal.lf
mzb =(x+15) and the mze =
(2x+15). Then find the value of
x in degree.
6 b
a
m
C с
d
f
e
n
g
h​

Answer 1

Answer:

mzb+mze=180

x+15+2x+15=180

3x+30=180

3x=180-30

x=150/3

x=50