3 power log root x at the base root 3 + 9 power log x at the base of 3 is
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3log3(x)+xlog3(x)=162
But 3log3(x)=x and log3(xlog3(x))=(logx(3))2 . Therefore xlog3(x)=3(logx(3))2 .
Let y=log3(x) , then 3y+3y2=162 . This clearly has two solutions, y a little more than 2 and y a little less than −2 . I.e. x is a little more than 9 or x is a little less then 1/9 .
To solve this you will need to use numerical approximations. The simplest method is repeated bisection. Find 3y+3y2 when y=2 and when y=3 . One is smaller than 162 , and one is greater. Take the average. At each step you get an interval surrounding the answer. Keep bisecting the interval between the two closest approximations until the answer is accurate enough for your purposes.
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