Question

3. PQRS is a square and ∆SRM is an equielateral∆ on the
same base SR Prove that (1)∆PSM=~ ∆QAM
(2) PM +QM
(3)SPM = 15°​

Answer 1

Step-by-step explanation:

∠PSR=∠QRS=90

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Now In △SRT

∠TSR=∠TRS=60

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∠PSR+∠TSR=∠QRS+∠TRS

⟹∠TSP=∠TRQ

Now in △TSP and △TRQ

TS=TR

∠TSP=∠TRQ

PS=QR

Therefore , △TSP≡△TRQ

So PT=QT

(ii) Now in △TQR,

TR=QR(RQ=SR=TR)

∠TQR=∠QTR

And ∠TQR+∠QTR+∠TRQ=180

⟹∠TQR+∠QTR+∠TRS+∠SRQ=180

⟹2(∠TQR)+60+90=180 (∠TQR=∠QTR)

2(∠TQR)=30

⟹∠TQR=15

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