Question

3. Predict the period and group of the element having outer electronic configuration
3s23p4 in the modern periodic table. Pls answer​

Answer 1

Answer:

period 3

group 16

Explanation:

Maximum principal number = No of period.

No of group end with p -orbital electrons=12+No of electrons in P-orbital

Answer 2

Answer:

The given element is in period 3, group 16 and belongs to the p-block.

Explanation:

This can be determined as:

The energy level( or principal quantum number) in which the outermost electrons are found gives us the period in the periodic table.

Here, outermost electrons are located in n= 3.

Also, the element is a p-block element as evident from the configuration of the outermost electrons( 3p4).

To find the group number in case of an element belonging to the p-block:

Total number of electrons in valence shell+ 10 Here, total electrons is 6 ( 2+4) so the group is 16.