Question

3. Prove that 3√2 is an irrational number.​

Answer 1

Step-by-step explanation:

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational number

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Answer 2

Answer:

hence proved

Step-by-step explanation:

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