3. Prove that 4 sin sin(60° + ) sin(60° − ) = sin3
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4 sin sin(60° + ) sin(60° − ) = sin3
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Answer:
Step-by-step explanation:
Given 4 sin a sin(60-a) sin(60 + a) can be written as
4 sin a ((sin 60 - a) + sin (60 - a))
4 sin a(sin^2 60 - sin^2 a)
4 sin a((root 3/2)^2 - sin ^2 a)
4 sin a(3/4 - sin^2 a)
4 ( 3 sin a - 4 sin^3 a/4)
4(1/4(sin 3a)
sin 3a.
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