3) Prove that cot² X sec² = cot²+ 1.
Answers
Answered by
0
Step-by-step explanation:
cot^2 x + 1 = cos^2 x / sin^2 x + 1
= cos^2x + sin^2x // sin^2x
= 1 / sin^2x
multiply and divide by cos^2 x we get,
cot^2 x + 1 = cos^2 x / sin^2 x × 1 / cos^2 x
= cot ^2 x × sec^2 x
Similar questions