Question

3. Prove that:
(sec A+ tan A) (1-sin A) = cos A
what is the answer​

Answer 1

Step-by-step explanation:

see the attachment....

Answer 2

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Answer:

$LHS\\\\=>(secA+tanA)(1-sinA)\\\\=>(\frac{1}{cosA}+\frac{sinA}{cosA} ).(1-sinA) )\\\\=>\frac{(1+sinA)}{cosA}.(1-sinA) \\\\=>\frac{1-sin^2A}{cosA} \\\\=>\frac{cos^2A}{cosA} \\\\=>cosA\\\\=>RHS\\\\Hence.Proved$

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