Question

3. Prove that the 7 root 5 is irrational ​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

Let us assume that 7√5 is rational number

Hence, 7√5 can be written in the form of a/b where a, b(b not equal to 0) are co-prime

7√5 = a/b

√5 = a/7b

here √5 is irrational and a/7b is rational

as Rational=Irrational

Therefore, 7√5 is irrational

please mark as brainilist and hit like

Answer 2

Answer:

Because a,b,are 7 integers 7b-ab is rational, implying that √5 is rational. But this contradicts with the fact that √5 is irrational. The contradiction is because of the incorrect assumption that 7-√5 is rational.;We can conclude that 7-√5 is irrational.

I HOPE IT HELPS YOU